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HOW TO FIND 30 AND 60 DEGREES FOR SIN,COS AND TAN

HOW TO FIND 30 AND 60 DEGREES FOR SIN,COS AND TAN using one of the triangle I.e right angled triangle opp square= hyp square - adj square opp square = 2^2 - 1^2 opp square = 4 - 1=3 opp = root 3. Then... sin30 degree = 1/2 = 0.5 cos30 degree = root 3/2 = 0.8660 tan30 degree = sin30 degree/ cos30 degree = 0.5/0.8660= root 3/3 or 0.5774. sin60 degree = root 3/2= 0.8660 cos60 degree = 1/2= 0.5 tan60 degree = 0.8660/0.5 = root 3/1= root 3
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Bearing and distance- City A is 300km deu east of city B, city C is 200km on a bearing of 123degress from city B. How far is it from C to A

Bearing and distance- City A is 300km due east of city B, city C is 200km on a bearing of 123degress from city B. How far is it from C to A... Solution Using the cosine rule formula a^2= b^2+c^2-2bccosA So therefore, b^2=a^2+c^2-2acCosB b(squared) = 200squared+300squared-2(200*300)cos33 = 40000+90,000-120,000cos33 =130,000-100640.47 =29359.53 b= square root of 29359.53 b=171.34... You find it simple? comment below
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MATHS TRICK: HOW TO EASILY MULTIPLY NUMBERS OF THE SAME DIGIT THAT ENDS WITH 5

Good day Maths geniuses,Todayi wil tutoring on how to find the square root of a Number.. HOW TO FIND THE SQUARE ROOT OF A DIGIT THAT HAS A PERFECT SQUARE Numbers that has a perfect square are numbers that their square root is a whole number without decimal or remainder.. All you need to solve this is your book,biro and your understanding...Below are the steps to take : 1. Subtract odd numbers starting from 1 from the number you want to look for it's square root till you get 0. 2 . Count the numbers of odd numbers you used and that's the square root of the number.That's all E.g Find the square root of 9 solution 9 - 1=8 , 8-3=5 and 5-5=0. That's all...Now,how many old numbers did i use to subtract..3 right.1,3,and 5 which means the square root 9 is 3
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